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Sideways movement in a slightly wider range remains above the invalidation point on the hourly chart.

The Elliott wave count is changed slightly but the outlook is essentially the same.

Summary: The trend is still down, but a bear market rally continues and is not done yet. It may end towards the middle or end of this week. A new high above 2,116 is expected. Short term more sideways movement should remain above 2,066.69 and be followed by a short sharp thrust upwards. Thereafter, the downwards trend should resume in force. This bear market rally is extremely unlikely to make a new all time high. It is expected to stop before 2,134.72.

To see how each of the bull and bear wave counts fit within a larger time frame see the Grand Supercycle Analysis.

To see last analysis of weekly and monthly charts click here.

If I was asked to pick a winner (which I am reluctant to do) I would say the bear wave count has a higher probability. It is better supported by regular technical analysis at the monthly chart level, it fits the Grand Supercycle analysis better, and it has overall the “right look”.

New updates to this analysis are in bold.



S&P 500 daily 2015
Click chart to enlarge.

Cycle wave IV should exhibit alternation to cycle wave II.

Cycle wave II was a shallow 0.41 zigzag lasting three months. Cycle wave IV should exhibit alternation in structure and maybe also alternation in depth. Cycle wave IV may end when price comes to touch the lower edge of the teal channel which is drawn about super cycle wave V using Elliott’s technique (see this channel on weekly and monthly charts).

Cycle wave IV may end within the price range of the fourth wave of one lesser degree. Because of the good Fibonacci ratio for primary wave 3 and the perfect subdivisions within it, I am confident that primary wave 4 has its range from 1,730 to 1,647.

If a zigzag is complete at the last major low as labelled, then cycle wave IV may be unfolding as a flat, combination or triangle.

Primary wave B or X is an incomplete zigzag unfolding upwards. If cycle wave IV is an expanded flat correction, then primary wave B may make a new high above the start of primary wave A at 2,134.72. If cycle wave IV is a combination, then primary wave X may make a new high above the start of primary wave W. There is no upper invalidation point for these reasons.

Primary wave A or W lasted three months. When it arrives primary wave Y or C may be expected to also last about three months.

Intermediate waves (A) and (B) together lasted a Fibonacci 34 days within primary wave B or X. So far intermediate wave (C) has lasted eleven days. It may end in a further two days to total a Fibonacci thirteen.


S&P 500 daily 2015
Click chart to enlarge.

Cycle wave IV may unfold as a shallow triangle. This would provide alternation with the 0.41 zigzag of cycle wave II.

Primary wave B may be unfolding as a zigzag. Primary wave B may make a new high above the start of primary wave A at 2,134.72 as in a running triangle. There is no upper invalidation point for this wave count for that reason.

The whole structure moves sideways in an ever decreasing range. The purpose of triangles is to take up time and move price sideways. A possible time expectation for this idea may be a total Fibonacci eight or thirteen months, with thirteen more likely. So far cycle wave IV has lasted six months.


S&P 500 hourly 2015
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Today the hourly charts are different. Both ideas presented work in exactly the same way for the bull and bear wave counts, and both see a fourth wave correction continuing sideways.

This first idea I consider slightly less likely than the second idea presented for the hourly bear wave count.

Minor wave 4 may be continuing sideways as a double combination. This would provide structural alternation with the zigzag of minor wave 2.

Minor wave 2 was relatively shallow at 0.44 the depth of minor wave 1. At its end, minor wave 4 may have little alternation in depth. Alternation is a guideline, not a rule. As long as there is some alternation, that is enough.

The first structure in the double would be a completed zigzag labelled minute wave w. The double is joined by a three, a zigzag in the opposite direction labelled minute wave x. The second structure in the double is a flat correction labelled minute wave y.

Both the A and B waves subdivide as threes within minute wave y. Minuette wave (b) is a 0.97 depth of minuette wave (a) meeting the minimum requirement of 0.9 for a B wave within a flat correction.

At 2,078 minuette wave (c) would reach 1.618 the length of minuette wave (a). This would see minor wave 4 end very close to the 0.382 Fibonacci ratio at 2,077.

It it gets that far, minor wave 4 may find support at the lower edge of the black channel copied over from the daily chart.

Minor wave 5 upwards would most likely be about equal in length with minor wave 1 and be about 47.30 points long.

Minor wave 4 may not move into minor wave 1 price territory below 2,066.69.



S&P 500 daily 2015
Click chart to enlarge.

It is possible to see cycle wave IV a completed flat correction. This would provide some structural alternation with the zigzag of cycle wave II.

This is a regular flat but does not have a normal regular flat look. Primary wave C is too long in relation to primary wave A. Primary wave C would be 3.84 short of 4.236 the length of primary wave A. While it is possible to also see cycle wave IV as a complete zigzag (the subdivisions for that idea would be labelled the same as the bear wave count below, daily chart) that would not provide structural alternation with the zigzag of cycle wave II, and so I am not considering it.

This idea requires not only a new high but that the new high must come with a clear five upwards, not a three.

At 2,562 cycle wave V would reach equality in length with cycle wave I. Cycle wave I was just over one year in duration so cycle wave V should be expected to also reach equality in duration. Cycle degree waves should be expected to last about one to several years, so this expectation is reasonable. It would be extremely unlikely for this idea that cycle wave V was close to completion, because it has not lasted nearly long enough for a cycle degree wave.

I added a bear market trend line drawn using the approach outlined by Magee in “Technical Analysis of Stock Trends”. When this lilac line is clearly breached by upwards movement that shall confirm a trend change from bear to bull. The breach must be by a close of 3% or more of market value. If it comes with a clear five up, then this wave count would be further confirmed.

While price remains below the bear market trend line, we should assume the trend remains the same: downwards.

Intermediate wave (1) is a complete five wave impulse and intermediate wave (2) is a complete three wave zigzag. Subdivisions at the hourly chart level would be the same for this wave count as for the other two wave counts; A-B-C of a zigzag subdivides 5-3-5, exactly the same as 1-2-3 of an impulse.

For this wave count, when the next five up is complete that would be intermediate wave (3). Within intermediate wave (3), no second wave correction may move beyond the start of its first wave below 2,019.39.

This wave count does not have support from regular technical analysis and it has a big problem of structure for Elliott wave analysis. I do not have confidence in this wave count. It is presented as a “what if?” to consider all possibilities.



S&P 500 daily bear 2015
Click chart to enlarge.

This bear wave count has a better fit at Grand Super Cycle degree and is better supported by regular technical analysis at the monthly chart level. But it is a huge call to make, so I present it second, after a more bullish wave count, and until all other options have been eliminated.

There are two ideas presented in this chart: a huge flat correction or a double flat / double combination. The huge flat is more likely. They more commonly have deep B waves than combinations have deep X waves (in my experience).

A huge flat correction would be labelled super cycle (a)-(b)-(c). It now expects a huge super cycle wave (c) to move substantially below the end of (a) at 666.79. C waves can behave like third waves. This idea expects a devastating bear market, and a huge crash to be much bigger than the last two bear markets on the monthly bear chart.

The second idea is a combination which would be labelled super cycle (w)-(x)-(y). The second structure for super cycle wave (y) would be a huge sideways repeat of super cycle wave (a) for a double flat, or a quicker zigzag for a double combination. It is also possible (least likely) that price could drift sideways in big movements for over 10 years for a huge triangle for super cycle wave (y).

The bear wave count sees a leading diagonal for a primary degree first wave unfolding. Within leading diagonals, the first, third and fifth waves are most commonly zigzags but sometimes may appear to be impulses. Here intermediate wave (1) is seen as a complete zigzag.

Intermediate wave (2) is an incomplete zigzag within the leading diagonal. It may not move beyond the start of intermediate wave (1) above 2,134.72. This wave count expects minor wave C to end midway within its channel, above the end of minor wave A at 2,116.48 but not above 2,134.72.


S&P 500 daily bear 2015
Click chart to enlarge.

Because I favour the bear wave count (because it is better supported by regular technical analysis and Elliott wave analysis at the monthly chart level), I will present the favoured idea for this fourth wave correction for the bear hourly wave count.

At this stage, sideways movement fits as an incomplete regular contracting or barrier triangle. This is supported by MACD being flat and hovering close to the zero line.

Within the triangle, minuette wave (c) may be either complete at Monday’s low or close to completion. It may not move beyond the end of minuette wave (a) below 2,070.29.

A zigzag upwards for minuette wave (d) may not move above the end of minuette wave (b) at 2,094.12 for a contracting triangle when minuette wave (c) is done. For a barrier triangle minuette wave (d) may end about the same level as minuette wave (b), as long as the (b)-(d) trend line remains essentially flat. What this means in practice is that minuette wave (d) may end slightly above 2,094.12 and the triangle would remain valid. This is the only Elliott wave rule which is not black and white.

The following and final wave of the triangle for minuette wave (e) should be a zigzag which may not move beyond the end of minuette wave (c).

The whole thing moves sideways in an ever decreasing range. It may see minute wave iv end close to the 0.236 Fibonacci ratio of minute wave iii at 2,085, which would provide better alternation in depth with the still shallow zigzag of minute wave ii. A triangle would provide perfect alternation with the zigzag.

This idea expects more sideways movement for another one to three days possibly. Minor wave C may end in fourteen days, one longer than a Fibonacci thirteen. Triangles are time consuming. Their purpose is to take up time, move price sideways, and test our patience.


S&P 500 daily 2015
Click chart to enlarge. Chart courtesy of

Daily: A sharp increase in volume for Monday’s red candlestick supports downwards movement, but volume is still light though. Overall, price is moving sideways and volume is declining to light. This supports the Elliott wave count which expects that currently a correction is unfolding.

ADX still indicates the market is not trending but consolidating. A range bound trading approach would expect some more upwards movement from here to not end until price finds resistance at one of the two upper horizontal trend lines and Stochastics is overbought at the same time.

A note on Dow Theory: for the bear wave count I would wait for Dow Theory to confirm a huge market crash. So far the industrials and the transportation indices have made new major swing lows, but the S&P500 and Nasdaq have not.

S&P500: 1,820.66
Nasdaq: 4,116.60
DJT: 7,700.49 – this price point was breached.
DJIA: 15,855.12 – this price point was breached.

To the upside, for Dow Theory, I am watching each index carefully. If any make new all time highs, that will be noted. If they all make new all time highs, then a continuation of a bull market would be confirmed. So far none have made new all time highs.

This analysis is published about 07:49 p.m. EST.