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Yesterday’s analysis expected a little more upwards movement to complete a second wave correction, which is what happened.

Summary: A third wave downwards has most likely begun. It is either a third wave within an impulse, or a third wave of an ending expanding diagonal. The target for this third wave is at 1,788. If we see a new low below 1,814.36 this week then the trend at minor degree will be confirmed as downwards.

This analysis is published about 07:52 p.m. EST. Click on charts to enlarge.

Bullish Wave Count.

The aqua blue trend lines are critical for all wave counts. Draw the first trend line from the low of 1,158.66 on 25th November, 2011 to the next swing low at 1,266.74 on 4th June, 2012. Create a parallel copy and place it on the low at 1,560.33 on 24th June, 2013. While price remains above the lower of these two aqua blue trend lines we must assume the trend remains upwards. This is the main reason for the bullish wave count being my main wave count.

S&P 500 daily 2014

This bullish wave count expects a new bull market began at 666.79 for a cycle wave V. Within cycle wave V primary waves 1 and 2 are complete. Within primary wave 3 intermediate wave (1) is complete at 1,850.84.

Intermediate wave (2) should find some support about the lower of the two aqua blue trend lines, but it must overshoot the lower trend line for minor wave C to move below the end of minor wave A. An overshoot of up to 3% (56.92 points) of market value is acceptable.

There is some precedent for a small breach of the lower aqua blue trend line: in November 2012 it was breached by 1.5% of market value. Small overshoots like this can happen.

I do not have a target for minor wave C downwards for you. If it were to reach 1.618 the length of minor wave A then downwards movement would breach the lower aqua blue trend line by more than 3%. If this wave count is correct then that should not happen. We may not see a ratio between minor waves A and C, which is not unusual for the S&P.

When I know where minute waves iii and iv within minor wave C have ended then I will use the ratios within minor wave C between minute waves i, iii and v to calculate a target for it to end. I will only be able to do this for you towards the end of minor wave C.

Minor wave A lasted 14 sessions and minor wave B lasted 41 sessions. Minor wave C may last up to a Fibonacci 55 sessions and it would still have the “right look”.

For this bullish wave count when intermediate wave (2) is complete then very strong sustained upwards movement would be expected as an intermediate degree third wave within a primary degree third wave upwards unfolds.

Main Hourly Wave Count.

S&P 500 hourly 2014

This main hourly wave count looks at the structure of minor wave C downwards as an impulse. This is more likely as impulses for C waves are more common than ending diagonals (alternate below). This main wave count also fits best with seeing the downwards wave labeled minuette wave (b) as a three.

Minute wave iii downwards has begun. Within it minuette wave (i) subdivides as a leading expanding diagonal. Second waves following leading diagonals in first wave positions are normally very deep. Minuette wave (ii) is now a completed zigzag and is a deep 87% correction of minuette wave (i).

At 1,825 minuette wave (iii) would reach 1.618 the length of minuette wave (i). Minuette wave (iii) downwards should show very strong downwards momentum.

At 1,788 minute wave iii would reach 1.618 the length of minute wave i.

Movement below 1,814.36 would invalidate the alternate daily wave count below and provide confirmation that the trend at minor degree is downwards.

S&P 500 5 minute 2014

Alternate Hourly Wave Count.

S&P 500 hourly alternate 2014

The other possible structure for minor wave C downwards is an ending diagonal.

Within an ending diagonal all the sub waves must subdivide as single zigzags. This fits for minute wave i downwards, although within it minuette wave (c) does not fit as well as a five wave structure.

Minute wave ii may be complete as an .85 correction of minute wave i. This is just longer than the common length for second and fourth waves within diagonals as between .66 to .81.

Minute wave iii downwards must subdivide as a single zigzag and must move beyond the end of minute wave i below 1,814.36. At 1,790 minuette wave (c) would reach 2.618 the length of minuette wave (a).

The diagonal must be expanding in order for minor wave C to reach below the end of minor wave A at 1,737.92. This would require minute wave iii to be longer than 82.92 points, the length of minute wave i.

Daily Alternate Wave Count.

S&P 500 daily alternate 2014

It is possible that intermediate wave (1) is not over and that within it minor wave 5 is unfolding as an ending contracting diagonal.

Within an ending diagonal all the subwaves may only subdivide as single zigzags.

The diagonal is contracting because minute wave iii is shorter than minute wave i, and minute wave iv is shorter than minute wave ii. The trend lines converge.

Minute wave ii was .55 correction of minute wave i, and minute wave iv was a .52 correction of minute wave iii. Both of these corrections are less than the common length for second and fourth waves within diagonals of between .66 to .81. This reduces the probability of this alternate wave count, and it gives the possible diagonal an atypical look. However, with continuing sideways movement the main wave count is starting to have an odd look; minor wave C there would have to significantly breach the lower aqua blue trend line to avoid a truncation, and this would look unusual.

I am at this stage more seriously considering this alternate.

This wave count would be confirmed with movement above 1,897.28. If the last upwards wave for minute wave v subdivides clearly as a single zigzag then this would be my only wave count.

Because the diagonal is contracting, and because minute wave iii is shorter than minute wave i, minute wave v may not be longer than equality with minute wave iii. This maximum limit is at 1,973.72.

Minute wave v would most likely end at the upper 1-3 trend line of the diagonal.

On the five minute chart minuette wave (b) may now be a complete double zigzag.

S&P 500 5 minute alternate 2014

Bearish Alternate Wave Count.

S&P 500 daily bear 2014

This bearish wave count expects that the correction was not over at 666.79, and that may have been just cycle wave a of a huge expanded flat for a super cycle wave II. Cycle wave b upwards is a close to complete zigzag.

Within flat corrections the maximum common length of B waves in relation to A waves is 138%. So far cycle wave b is a 141% correction of cycle wave a. For this reason only this wave count is an alternate.

Within primary wave C of the zigzag intermediate wave (4) would be incomplete.

The subdivisions for intermediate wave (4) would be the same as the main wave count for intermediate wave (2). I would expect it to end at the lower aqua blue trend line.

At 2,190 primary wave C would reach 1.618 the length of primary wave A. When intermediate wave (4) is complete I would recalculate this target at intermediate degree. I have found Fibonacci ratios between actionary waves (1, 3 and 5) of impulses are more reliable than between A and C waves within zigzags for the S&P500.

If intermediate wave (5) lasts about five to six months it may end about October this year.