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Yesterday’s analysis expected two more days of very choppy overlapping movement to complete this fourth wave correction. We now have one more day of this overlapping movement, and the structure is incomplete. It may end tomorrow.

Click on the charts below to enlarge.

S&P 500 daily 2013

This wave count has a higher probability than the bullish alternate. Upwards movement over the last 4 1/2 years subdivides best as a zigzag. If something is “off” about the supposed recovery then it must be a B wave because there is plenty that is off in this scenario in terms of social mood.

Minor waves 1, 2 and 3 are complete. Minor wave 4 is most likely incomplete. If it ends on 9th January, 2014 it would have lasted a Fibonacci 8 days.

We may be about to see a larger fractal at minor wave degree of the structure within minor wave 1 at minute wave degree; there the first wave was extended, the third wave was shorter, and the fifth wave was shorter still.

Intermediate wave (3) is just 0.76 points short of 2.618 the length of intermediate wave (1). We may not see a Fibonacci ratio between intermediate wave (5) and either of (3) or (1).

Intermediate wave (1) lasted 18 days. Intermediate wave (5) may last a total of a Fibonacci 89 days which would see it end on 10th February, 2014. However, Fibonacci time relationships are not very reliable for the S&P. This is a rough guideline only,

At super cycle degree the structure is an expanded flat correction. Within the flat the maximum common length of cycle wave b is 138% the length of cycle wave a, and this is achieved at 1,858.03. When cycle wave b is longer than the common length of cycle wave a then the probability that an expanded flat is unfolding would reduce and it would be more likely that a long term bull market is underway. Above 1,858.03 I will swap this main wave count over with the bullish alternate.

S&P 500 hourly 2013

Minute wave y has begun and looks like it is unfolding as a flat correction. Within it the downwards movement labeled minuette wave (a) subdivides best as a zigzag on the five minute chart. Upwards movement labeled minuette wave (b) is unfolding as a flat correction.

Within minuette wave (b) subminuette wave c would reach equality with subminuette wave a at 1,841. Because subminuette wave b is over 90% but less than 105% the length of subminuette wave a this flat is a regular flat. Regular flats most commonly have C waves which are close to equality with their A waves.

When minuette wave (b) is completed then I would expect a five wave structure downwards for minuette wave (c). This would complete the second flat correction of minute wave y, and so complete minor wave 4 as a double flat.

Minute wave y is likely to end about the same level of minute wave w at 1,828 because the purpose of double flats is to take up time and move price sideways, so the second structure usually ends about the same level as the first.

Minor wave 4 may end close to the 0.236 Fibonacci ratio at 1,825. This gives us a three point target zone which may be reached tomorrow if minor wave 4 is to last a Fibonacci eight days in total.

Minor wave 4 may not move into minor wave 1 price territory. This wave count is invalidated with movement below 1,811.22.

S&P 500 5 minute 2013

Bullish Alternate Wave Count.

S&P 500 daily alternate bullish 2013

It is possible that a new cycle degree bull market began at 666.79. So far it is not yet halfway through, and I would expect it to last for a few years (at least five more years and probably longer).

The current upwards impulse, labeled intermediate wave (5) for the main wave count and minor wave 5 for this alternate is incomplete. The structure within the final fifth wave is the same, and the structure on the hourly chart is the same. Targets would be the same for this bullish wave count. This wave count does not diverge with the main wave count, and it will not for several weeks or a couple of months or so yet.

The maroon – – – channel is an acceleration channel drawn about primary waves 1 and 2 on the monthly chart (it is drawn in exactly the same way on the main wave count, but there it is termed a corrective channel). I would not expect intermediate wave (2) to breach this channel because a lower degree (intermediate) wave should not breach an acceleration channel of a higher degree (primary) first and second wave.