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DJIA Elliott Wave Technical Analysis – 17th May, 2013

by Lara · May 19th, 2013 · DOW Analysis Weekly, SPX500 Daily & DJIA Weekly · No Comments

Last analysis expected more upwards movement from the Dow for the week which is what has happened.

The wave count remains the same.

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S&P 500 Elliott Wave Technical Analysis – 17th May, 2013

by Lara · May 18th, 2013 · SPX500 Analysis Daily, SPX500 Daily & DJIA Weekly · No Comments

Last analysis expected it was most likely we should see overall downwards movement which should be choppy and overlapping, for another one to two sessions. This is not what happened. Price has moved higher so the probability the correction was brief and is over has increased.

I have two hourly wave counts for you today with the main wave count having a higher probability.

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AAPL Elliott Wave Technical Analysis – 16th May, 2013

by Lara · May 17th, 2013 · Apple · No Comments

Analysis of AAPL at the beginning of this week expected upwards movement extremely likely to move above 469.95. Price did not move higher, and although the wave count is not yet invalidated at the hourly chart level it does not look right. I have adjusted the wave count at minor degree today.

Click on the charts below to enlarge.

AAPL Elliott Wave Chart 2013

This wave count expects a five wave impulse for a cycle degree wave a is unfolding to the downside. Within the impulse primary waves 1 and 2 are complete. Primary wave 3 is extending. Within primary wave 3 intermediate waves (1) and (2) are complete. Intermediate wave (2) failed to move above the high of minor wave A at 469.95 and has completed as a rare running flat.

Within intermediate wave (2) minor wave C is just 2.17 short of 1.618 the length of minor wave A.

At 289.78 intermediate wave (3) would reach equality in length with intermediate wave (1). When there is more structure within intermediate wave (3) to analyse I will add a target calculation at minor degree for it to end, so this target will probably change.

At 272 primary wave 3 would reach 1.618 the length of primary wave 1. This long term target is still months away.

Within intermediate wave (3) no second wave correction may move beyond the start of its first wave. This wave count is invalidated with movement above 465.75.

I have considered various possibilities for this downwards movement from the high labeled primary wave 2. What is most clear is that the middle of primary wave 3 has not yet passed because we have not seen momentum increase beyond that seen for primary wave 1. Primary wave 3 cannot be complete.

AAPL Elliott Wave Chart 2013

Within intermediate wave (2) minor wave C subdivides perfectly as an impulse.

Ratios within minor wave C are: minute wave iii is 3.97 longer than 1.618 the length of minute wave i, and minute wave v is 1.21 longer than equality with minute wave i. This is a most typical impulsive structure which adds confidence that this wave count is correct.

Ratios within minute wave iii are: minuette wave (iii) has no Fibonacci ratio to minuette wave (i), and minuette wave (v) is just 0.07 short of 0.618 the length of minuette wave (i).

Ratios within minuette wave (iii) within minute wave iii are: subminuette wave iii is 1.41 longer than 2.618 the length of subminuette wave i, and subminuette wave v is 0.42 short of 0.382 the length of subminuette wave (iii).

Ratios within minute wave v are: minuette wave (iii) is 1.24 longer than 4.236 the length of minuette wave (i), and minuette wave (v) is 0.19 short of equality with minuette wave (i).

Ratios within minuette wave (iii) within minute wave v are: subminuette wave iii is just 0.13 longer than 1.618 the length of subminuette wave i, and subminuette wave v is 0.51 longer than 1.618 the length of subminuette wave iii.

Ratios within subminuette wave v of minuette wave (iii) of minute wave v are: micro wave 3 is 0.42 short of 1.618 the length of micro wave 1, and micro wave 5 is 0.36 longer than 0.618 the length of micro wave 1.

A channel drawn about minor wave C using Elliott’s technique fits this movement perfectly and is now clearly breached.

Within the new downwards movement to begin intermediate wave (3) the first impulse downwards is incomplete. Within minuette wave (iii) subminuette wave iii is just 0.02 longer than 2.618 the length of subminuette wave i. At 413.75 subminuette wave v would reach 0.618 the length of subminuette wave iii.

We may draw a channel about minuette wave (iii) downwards. Draw the first trend line from the highs of subminuette waves ii to iv, then place a parallel copy upon the low of subminuette wave iii. I would expect subminuette wave v to end about midway within this channel, or to find support about the lower edge if it moves down that low.

Within minutte wave (iii) if subminuette wave iv moves any higher it may not move into subminuette wave i price territory. This wave count is invalidated with movement above 450.48.

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AAPL Elliott Wave Technical Analysis – Video – 16th May, 2013

by Lara · May 17th, 2013 · Apple · 9 Comments

This video is different from how I normally present my analysis. I have been asked to show how I use Motive Wave, and how I decide on a wave count. I have tried to do both here.

This video is simply a recording of how I did today’s AAPL analysis. It is over 20 minutes because that’s how long the process took today.

* my wallpaper is a picture of a Kakapo named Sirocco. He’s a member of one of the rarest species of parrot in the world, there are only 125 Kakapo left. They can survive over 100 years and breed infrequently. Kakapo are flightless and have a really weird “boom” for a mating call.

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S&P 500 Elliott Wave Technical Analysis – 16th May, 2013

by Lara · May 17th, 2013 · SPX500 Analysis Daily, SPX500 Daily & DJIA Weekly · No Comments

Yesterday’s analysis expected upwards movement to a short term target at 1,666 to 1,669 before price turned downwards to begin a fourth wave correction. We did see upwards movement but it was very slight and fell short 5.49 points short of the target.

A recent increase in upwards momentum has indicated the labeling within intermediate wave (C) was incorrect. I have adjusted this labeling but it makes little difference to expected direction. It will however affect target calculation.

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GOLD Elliott Wave Technical Analysis – Video – 15th May, 2013

by Lara · May 16th, 2013 · Gold · No Comments

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GOLD Elliott Wave Technical Analysis – 15th May, 2013

by Lara · May 16th, 2013 · Gold · No Comments

Last week’s analysis of gold expected downwards movement to a target for the week at 1,416. So far price has reached 28.74 below the target.

Price is on track to meet the first target on the daily chart at 1,276.

Click on the charts below to enlarge.

Gold Elliott Wave Chart Daily 2013

This daily chart focuses on the new downwards trend of primary wave C.

Within primary wave C intermediate waves (1) and (2) are complete. Intermediate wave (3) is underway and may have just passed the middle of it.

Within intermediate wave (3) minor waves 1 and 2 are complete and minor wave 3 may have just passed its middle.

Within minor wave 3 minute waves i, ii, iii and iv are complete. Minute wave v has just begun. This was confirmed this week with a clear channel breach of the small channel I had containing the upwards zigzag of minute wave iv on last week’s chart.

Ratios within minute wave iii are: minuette wave (iii) has no Fibonacci ratio to minuette wave (i), and minuette wave (v) is 3.91 longer than 0.236 the length of minuette wave (iii). Minuette wave (v) is slightly truncated.

At 1,276 minute wave v would reach 1.618 the orthodox length of minute wave i. Because there is no Fibonacci ratio between minute waves i and iii I expect we shall see a Fibonacci ratio between minute wave v and either of iii or i.

Draw a channel about minor wave 3 using Elliott’s second technique. Draw the first trend line from the highs of minute waves ii and iv, then place a parallel copy upon the low of minute wave iii. Expect minute wave v to end midway within this channel most likely, or to find support at the lower edge if it gets down there. When this channel is breached by subsequent upwards movement then minor wave 3 should be over and minor wave 4 should be underway.

At 1,232 intermediate wave (3) would reach 4.236 the length of intermediate wave (1).

At 1,151 primary wave C would reach 1.618 the length of primary wave A.

Within minute wave v no second wave correction may move beyond the start of its first wave. This wave count is invalidated at minor degree with movement above 1,488.13.

GOLD Elliott Wave Chart Hourly 2013

Despite movement below the target for subminuette wave iii the structure is incomplete. The target was calculated at 1.618 the length of subminuette wave i. Subminuette wave iii has passed 1.618 and is very close to 2.618 the length of subminuette wave i. It may not exhibit a Fibonacci ratio to subminuette wave i. Ratios of actionary waves within it may be used to calculate the target when we have the ends of micro waves 3 and 4.

Ratios within micro wave 1 are: submicro wave (3) is 0.58 longer than 4.236 the length of submicro wave (1), and submicro wave (5) is 3.95 longer than 1.618 the length of submicro wave (3).

Ratios within submicro wave (3) of micro wave 1 are: minuscule wave 3 is 1.6 longer than equality with minuscule wave 1, and minuscule wave 5 is 0.26 short of 0.382 the length of minuscule wave 1.

Ratios within submicro wave (5) of micro wave 1 are: minuscule wave 3 is 0.90 short of 1.618 the length of minuscule wave 1, and minuscule wave 5 is 1.23 longer than equality with minuscule wave 1.

Within micro wave 3 submicro wave (3) is 4.10 short of 2.618 the length of submicro wave (1) (this is a 7.2% variation, I consider less than 10% acceptable).

Ratios within submicro wave (3) of micro wave 3 are: minuscule wave 3 has no Fibonacci ratio to minuscule wave 1, and minuscule wave 5 is 0.93 short of 0.618 the length of minuscule wave 1.

At 1,357 micro wave 3 would reach 1.618 the length of micro wave 1. This target should be met within the week.

Draw a channel about micro wave 3 using Elliott’s first channeling technique. Expect upwards movement for submicro wave (4) to find resistance at the upper edge of the channel. Expect submicro wave (5) to end either midway within the channel or to find support at the lower edge.

When subminuette wave iii is complete the following correction for subminuette wave iv should last about one session and may not move back into subminuette wave i price terrotory. This wave count is invalidated with movement above 1,441.48.

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S&P 500 Elliott Wave Technical Analysis – 15th May, 2013

by Lara · May 15th, 2013 · SPX500 Analysis Daily, SPX500 Daily & DJIA Weekly · No Comments

Yesterday’s analysis expected more upwards movement from the S&P 500 which is what happened. Price is now very close to the short term target. Price found resistance at the upper edge of the parallel channel on the hourly chart during Wednesday’s session. It may do the same tomorrow.

The wave count remains the same.

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US OIL Elliott Wave Technical Analysis – 14th May, 2013

by Lara · May 15th, 2013 · US Oil · No Comments

Last week’s analysis expected oil to move lower which is what has happened. The channel about the last upwards wave on the daily chart is now breached providing trend channel confirmation of a trend change back to the downside for oil.

Click on the charts below to enlarge.

US Oil Elliott Wave Chart Daily 2013

This wave count sees US Oil in a third wave downwards at intermediate degree, within a primary wave C down.

Within intermediate wave (3) minor waves 1 and 2 are complete.

Within minor wave 3 minute wave i may be unfolding as a leading diagonal. Within the leading diagonal minuette waves (ii) and (iv) must subdivide into zigzags, and minuette waves (i), (iii), and (v) are usually zigzags but may also subdivide as impulses. Second and fourth waves of diagonals are usually deep corrections, between 66% to 81%. Minuette wave (ii) is deeper at 94% and minuette wave (iv) is now 95%.

We now have a clear breach of the parallel channel containing the zigzag of minuette wave (iv) indicating this correction is over and the next wave down has begun.

Within the leading diagonal minuette wave (v) may not be truncated, it must move below 85.64.

The diagonal is expanding. We should expect minuette wave (v) to be longer than minuette wave (iii), to move below 85.05. However, I have seen diagonals where the third wave is still the longest, so this may not happen.

Draw a parallel channel about minuette wave (iv) using Elliott’s channeling technique. Draw the first trend line from the start of minuette wave (iv) to the low of subminuette wave b within it, then place a parallel copy upon the high of subminuette wave a within minuette wave (iv). We have seen this parallel channel clearly breached by downwards movement and now have confidence the correction is over and a fifth wave down has begun.

Minuette wave (iv) of the diagonal should overlap into minuette wave (i) price territory, but may not move beyond the start of minuette wave (ii) price territory. This wave count is invalidated with movement above 97.73

US Oil Elliott Wave Chart Hourly 2013

Since last analysis price has moved lower. The channel breach indicates a new wave down has begun which must subdivide into either a zigzag or an impulse. If it subdivides into a zigzag (most likely) then subminuette wave a within it must subdivide into a five wave structure, either a leading diagonal or an impulse.

I have considered various possibilities for movement downwards from the high at 97.14 labeled minuette wave (iv). The key seems to be the upwards movement labeled submicro wave (A) within micro wave 4. On the five minute chart this movement subdivides perfectly as a five wave impulse and it is not possible to see it as a zigzag. The correction cannot have ended there and so must move higher.

Within micro wave 4 submicro wave (B) subdivides nicely into a double zigzag. If this structure moves any lower, or continues further sideways, it may not move beyond the start of submicro wave (A) within the zigzag. This wave count is invalidated in the short term (prior to a five up for submicro wave (C) being complete) with movement below 93.36.

Submicro wave (C) must subdivide into a five wave structure to complete the zigzag for micro wave 4. Submicro wave (C) is very likely to end above the end of submicro wave (A) to avoid a truncation above 96.22.

Within the diagonal micro wave 4 should overlap into micro wave 1 price territory, but may not move beyond the end of micro wave 2. This wave count is invalidated with movement above 96.76.

The other possibility which may be unfolding to the downside would be an impulse. It too would require the completion of a zigzag with subdivisions labeled essentially the same as micro wave 4 here. The short term outlook would be the same.

When the zigzag of micro wave 4 is completed, if this wave count remains valid, then we should expect a fifth wave downwards which must make a new low below the end of micro wave 3 at 93.36 because the fifth wave of a leading diagonal may not be truncated.

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S&P 500 Elliott Wave Technical Analysis – 14th May, 2013

by Lara · May 14th, 2013 · SPX500 Analysis Daily, SPX500 Daily & DJIA Weekly · No Comments

Last analysis expected the S&P 500 had entered a fourth wave correction. The alternate hourly wave count looked at the possibility that the fourth wave had not yet arrived. Upwards movement confirms the alternate hourly wave count.

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